0=(x^2)-18x+32

Solution for 0=(x^2)-18x+32 equation:

0=(x^2)-18x+32

We move all terms to the left:

0-((x^2)-18x+32)=0

We add all the numbers together, and all the variables

-(x^2-18x+32)=0

We get rid of parentheses

-x^2+18x-32=0

We add all the numbers together, and all the variables

-1x^2+18x-32=0

a = -1; b = 18; c = -32;
Δ = b2-4ac
Δ = 182-4·(-1)·(-32)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-14}{2*-1}=\frac{-32}{-2}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+14}{2*-1}=\frac{-4}{-2}
=+2
$